how to throw the characters?

[iurceg]

I have a number of type double 12.2301000
I need to get 12.23

p.s. I do not need rounding.

[PsychoCoder]

You can use String.Format like this to only allow 2 decimal places:

String.Format("{0:0.00}", 123.4567);

You can also use regular expressions in the KeyPress event of your textbox like this:

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
	if (char.IsNumber(e.KeyChar) || e.KeyChar=='.')
	{
		if (Regex.IsMatch(textBox1.Text, "^\\d*\\.\\d{2}$")) 
			e.Handled=true;
	}
	else 
	e.Handled = e.KeyChar != (char)Keys.Back;
}

[iurceg]

PsychoCoder
Thanks for response but the first version is rounded.

String.Format("{0:0.00}", 123.4567);

The result is: 123.46 but i need 123.45 :)

[Stewart Ross]

@iurceg: what you are really asking is that the result should be rounded down in all cases, not rounded up when the next digit is 5 or more as is the normal practice. It is not correct to say you do not need rounding - truncation is still a form of rounding of the answer.

I'm not a c# person, so I don't know how to express it in c#, but one way to truncate a value to two decimal places is to multiply the double by 100, store the result in a longint, then divide the longint value by 100 to obtain your result (effectively truncating to two decimal places max).

You could also use integer division in place of the use of a longint, or whatever the C# equivalent of the VB Int function is to accomplish the same effect.

-Stewart