Calling Derived class method from base class reference

[vishalja1981]

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Please see simplified version of below program. First part of code declare several classes. Class A is simple class have one member method1. Class B and C both derived from A implement same member method1.
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I have arrayA of type A in main, this store instance of B and C. See main in code where I want to call method1 of B and C how I call that.

1. Class A
2. {
3. method1()
4. {
5. console.write(" XYZ");
6. }
7. }
   
8. Class B:A
9. {
10. new method1()
11. {
12. // some statement
13. }
14. }
    
15. Class C:A
16. {
17. new method1()
18. {
19. // some code
20. }
    
21. }
    
22. main()
23. {
24. arrayA.add(objB );
25. arrayA.add(objC );
    
26. foreach(A a in arrayA)
27. {
28. a.method1();
29. }
30. }

[GaryTexmo]

You can access the base class in both B and C. Perhaps something like this...?

...
public class B : A
{
  new method1() { ... }
  public CallBaseMethod1() { base.method1(); }
}

...

arrayA.add(objB);
arrayA.add(objC);
foreach(B b in arrayA)
{
  b.CallBaseMethod1();
}

Alternatively, in A you could make a method that does the work of A but call it from another method, then all your classes that inherit A will have two methods, one that's overridden and another that's not.

I don't know if there's a way to just force a call to the base method though. There might be, but I don't know what it is. Sorry!

[jkmyoung]

In your current context, A::Method1() would be called each time.
If you're trying to do what I think you're trying to do:
Declare A's method virtual.
Declare B and C's method as a override function.

http://www.codeproject.com/KB/cs/cs_methodoverride.aspx

[Christian Binder]

I think, you have to cast it to the correct type.

foreach(A a in arrayA)
{
  if(a is B)
    ((B)a).method1();
  elseif(a is C)
    ((C)a).method1();
  else
    a.method1();
}

If you don't need to instantiate objects of type A (A a = new A();),
you could make A's method1 abstract.

abstract class A {
  abstract void method1();
}

class B : A {
  override void method1() {
    // some code
  }
}

another way is to use delegates

private class B : A {
      void method1ofB() {
        // doing stuff of class B
      }
      
      public B() {
        Method1 = method1ofB;
      }
    }

    private class A {
      public Action Method1;

      private void method1ofA() {
        // some stuff of class A
      }

      public A() {
        Method1 = method1ofA;
      }
    }


// you'd call it this way:
A a1 = new A();
A a2 = new B();
a1.Method1();  // doing A's stuff
a2.Method1();  // doing B's stuff

[vishalja1981]

Thaks Guys. I got it. All of above works and I used making base class method virtual and derived override. It solved my needs.