question about the initialization of an array of generic queue

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Here are the codes

Queue<string>[] q = new Queue<string>[2];

Console.WriteLi ne(q[0].Count + "");

The program will crash since q[0] is null.

So my question is that what is the best way for new to initialize the array
with generic queue as the value?

I can do for statement and then do q[i] = new Queue<string>() ;

But,is there a better way to do it?

Thanks

Chris

[Marc Gravell]

Re: question about the initialization of an array of generic queue

But,is there a better way to do it?

No, not really. Array values initialize to their default values: 0 /
false / null / etc. Assuming you want each item in the array to be a
different queue, you will need to loop and create (new) a different
object for each.

Marc

[Ben Voigt [C++ MVP]]

Re: question about the initialization of an array of generic queue

chrisben wrote:

Here are the codes
>
Queue<string>[] q = new Queue<string>[2];
>
Console.WriteLi ne(q[0].Count + "");
>
The program will crash since q[0] is null.
>
So my question is that what is the best way for new to initialize the
array with generic queue as the value?
>
I can do for statement and then do q[i] = new Queue<string>() ;
>
But,is there a better way to do it?

Well, you can always write a reusable function for that:

static class ArrayHelper
{
static void FillUsingDefaul tConstructor<T( this T[] array) where T :
new
{
for( int i = 0; i < array.Length; i++ )
array[i] = new T();
}
}

Queue<string>[] q = new Queue<string>[2];
q.FillUsingDefa ultConstructor( );

>
Thanks
>
Chris

[Michael J. Ryan]

Re: question about the initialization of an array of generic queue

Why not use List<Queue<stri ng>?

On 10/15/2008 11:44 AM, chrisben wrote:

Here are the codes
>
Queue<string>[] q = new Queue<string>[2];
>
Console.WriteLi ne(q[0].Count + "");
>
The program will crash since q[0] is null.
>
So my question is that what is the best way for new to initialize the array
with generic queue as the value?
>
I can do for statement and then do q[i] = new Queue<string>() ;
>
But,is there a better way to do it?
>
Thanks
>
Chris

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