public static bool isodd(int i)
{
return ((i & 1) == 1);
}
can someone explain me how this is working
{
return ((i & 1) == 1);
}
can someone explain me how this is working
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Re: ((i & 1) == 1)
On 2008-06-26, joso <joso@hi.t-com.hrwrote:It's a simple test for oddness on an integer value. Any integer value that ispublic static bool isodd(int i)
{
return ((i & 1) == 1);
}
>
can someone explain me how this is working
odd will have a one in the ones column... So, the result of a bitwise and of
any integer value and one, can tell you if it is odd or not.
1111 & 0001 = 1
0111 & 0001 = 1
0100 & 0001 = 0
1110 & 0001 = 0
--
Tom Shelton
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Re: ((i & 1) == 1)
An integer is a basic type having a number of binary bits.
Depending on your processer architecture this might be 32 or 64 bits.
The binary and (&) operator performs a bitwise "AND" operation on the
integer which effectively removes all but the least significant bit of the
integer. This may be 1 or 0 depending on the value.
In the case that it is indeed 1, the number is odd.
Hope this was easily understood.
--
Bob Powell [MVP]
Visual C#, System.Drawing
Ramuseco Limited .NET consulting
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"joso" <joso@hi.t-com.hrwrote in message
news:g410fi$jac $1@ss408.t-com.hr...public static bool isodd(int i)
{
return ((i & 1) == 1);
}
>
can someone explain me how this is workingComment
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Re: ((i & 1) == 1)
Bob Powell [MVP] wrote:In C# an int is always 32 bit.An integer is a basic type having a number of binary bits.
>
Depending on your processer architecture this might be 32 or 64 bits.
Arne
Comment
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Re: ((i & 1) == 1)
"Arne Vajhøj" <arne@vajhoej.d kwrote in message
news:486436bf$0 $90270$14726298 @news.sunsite.d k...He didn't write 'int' but 'integer'. An integer is a mathematical concept,Bob Powell [MVP] wrote:>>An integer is a basic type having a number of binary bits.
>>
>Depending on your processer architecture this might be 32 or 64 bits.
In C# an int is always 32 bit.
>
Arne
an int in C# is an alias for a System.Int32 which is an integer represented
in the architecture as 32 bits as opposed to an Int64.
--
Joe Fawcett (MVP - XML)
Comment
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Re: ((i & 1) == 1)
Joe Fawcett wrote:How do you think that he think about integer as a mathematical type"Arne Vajhøj" <arne@vajhoej.d kwrote in message
news:486436bf$0 $90270$14726298 @news.sunsite.d k...He didn't write 'int' but 'integer'. An integer is a mathematical>Bob Powell [MVP] wrote:>>>>An integer is a basic type having a number of binary bits.
>>>
>>Depending on your processer architecture this might be 32 or 64 bits.
>In C# an int is always 32 bit.
concept, an int in C# is an alias for a System.Int32 which is an integer
represented in the architecture as 32 bits as opposed to an Int64.
when he write "An integer is a basic type having a number of binary
bits" ?
Besides it would be even worse if it were the case. Believing that
a mathematical concept depends on processor architecture to be
either 32 or 64 bit.
Arne
Comment
Comment