Capturing seperators with regex

[Nightcrawler]

I have the following regular expression: (\s+-\s+|\s+\/\s+|\s+\\\s+|
\t)

Is there a better way to write this? I am looking to capture the
following characters - / \ and tab. There can be 0, 1 or more space
before and after these seperators.

Right now it captures these characters if there is a 1 or more spaces
before and after each seperator. However, there are instances where
there will be 0 spaces before or after or both before and after.

Thanks

[Paul E Collins]

Re: Capturing seperators with regex

"Nightcrawl er" <thomas.zaleski @gmail.comwrote :

I have the following regular expression:
(\s+-\s+|\s+\/\s+|\s+\\\s+|\t )
>
Is there a better way to write this? I am looking to capture the
following characters - / \ and tab. There can be 0, 1 or more space
before and after these seperators.

If you want 0, 1 or more (instead of just one or more) you should use *
instead of +. In a regular expression, * means "zero or more" and +
means "one or more".

Eq.

[Ben Voigt [C++ MVP]]

Re: Capturing seperators with regex

Nightcrawler wrote:

I have the following regular expression: (\s+-\s+|\s+\/\s+|\s+\\\s+|
\t)
>
Is there a better way to write this? I am looking to capture the
following characters - / \ and tab. There can be 0, 1 or more space
before and after these seperators.

How about this?
"\\s*(?:[-/\\t]\s*)+"

>
Right now it captures these characters if there is a 1 or more spaces
before and after each seperator. However, there are instances where
there will be 0 spaces before or after or both before and after.
>
Thanks

[Nightcrawler]

Re: Capturing seperators with regex

Thanks! That helped!