Hi All,
I have the following in every column as shown below.Could you please let me know the formala for calculating the hours between two dates with times
ColumnK2 ColumnL2
05/11/2010 12:03:00 05/11/2010 13:03:00
ColumnM2
=TEXT((IF(L2=0, NOW(),L2))-K2,"h:mm:ss") gives value 0:1:00:00
Column K contains a Bug open date and Column L has the Bug Close date (that's why a if check is there , if a bug is not yet closed and has 0 value)
This formula is wrking fine except for case where the columns have the following values:-
ColumnK :12/10/2010 12:10:00
ColumnL :15/10/2010 12:32:00
Column M gets value as 0:22:00 but there is a difference of 2 days
If i make the formula as =TEXT((IF(L2=0, NOW(),L2))-K2,"D:h:mm:ss" )
then only i get 3:0:22:00
But what I want in ColumnM is ColumnL minus ColumnK value in hours
I know there are formulaes such as INT((K2-L2)*24) but that just gives me an incorrect value.
Please let me know if someone has a solution.
Thanks in advance
Titli
I have the following in every column as shown below.Could you please let me know the formala for calculating the hours between two dates with times
ColumnK2 ColumnL2
05/11/2010 12:03:00 05/11/2010 13:03:00
ColumnM2
=TEXT((IF(L2=0, NOW(),L2))-K2,"h:mm:ss") gives value 0:1:00:00
Column K contains a Bug open date and Column L has the Bug Close date (that's why a if check is there , if a bug is not yet closed and has 0 value)
This formula is wrking fine except for case where the columns have the following values:-
ColumnK :12/10/2010 12:10:00
ColumnL :15/10/2010 12:32:00
Column M gets value as 0:22:00 but there is a difference of 2 days
If i make the formula as =TEXT((IF(L2=0, NOW(),L2))-K2,"D:h:mm:ss" )
then only i get 3:0:22:00
But what I want in ColumnM is ColumnL minus ColumnK value in hours
I know there are formulaes such as INT((K2-L2)*24) but that just gives me an incorrect value.
Please let me know if someone has a solution.
Thanks in advance
Titli
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